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Types of number & HCF/LCM
Fractions, decimals, percentages
Indices and standard form
Bounds and estimation
Practice questions done
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Types of Number

Integers · Primes · HCF & LCM · Rational & Irrational · Ordering

Types of Number
Natural (ℕ): 1, 2, 3, 4, … (positive integers)
Integers (ℤ): …, −2, −1, 0, 1, 2, … (includes negatives)
Rational (ℚ): can be written as \(\frac{p}{q}\) where \(p, q\) are integers. Decimals terminate or recur.
Irrational: cannot be written as a fraction. e.g. \(\sqrt{2},\; \pi,\; e\)
Real (ℝ): all rational and irrational numbers
Prime Numbers

A prime has exactly two factors: 1 and itself. 1 is not prime.

2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47…
Prime factorisation
Express any integer as a product of primes. e.g. \(60 = 2^2 \times 3 \times 5\)
HCF & LCM
HCF
Highest Common Factor — largest number dividing both. Use prime factorisation: take minimum powers of common primes.
LCM
Lowest Common Multiple — smallest number both divide into. Take maximum powers of all primes.
Example: 12 = 2²×3, 18 = 2×3²
HCF = 2×3 = 6
LCM = 2²×3² = 36
Rounding & Bounds
Sig figs
Count from the first non-zero digit. 0.00472 to 2 s.f. = 0.0047
Dec places
Count from the decimal point. 3.1416 to 2 d.p. = 3.14
Rules
5 and above → round up. Below 5 → round down.
Upper & Lower Bounds
When \(x = 6.3\) cm (1 d.p.):
Lower bound = \(6.25\) cm
Upper bound = \(6.35\) cm

Interpretation: \(6.25 \leq x < 6.35\)
Trap: Upper bound is just below 6.35, not 6.35 itself (it's the value that would round up to 6.4).

Fractions, Decimals & Percentages

Converting between forms · Percentage change · Reverse percentage · Ratio

Fraction Operations
Add/Sub
Use LCM of denominators: \(\dfrac{1}{3}+\dfrac{1}{4}=\dfrac{4}{12}+\dfrac{3}{12}=\dfrac{7}{12}\)
Multiply
Top × top, bottom × bottom: \(\dfrac{2}{3}\times\dfrac{4}{5}=\dfrac{8}{15}\)
Divide
Flip and multiply: \(\dfrac{2}{3}\div\dfrac{4}{5}=\dfrac{2}{3}\times\dfrac{5}{4}=\dfrac{10}{12}=\dfrac{5}{6}\)
Simplify first — cancel common factors before multiplying to keep numbers smaller.
Percentage Calculations
% of amount
\(p\%\) of \(x = \dfrac{p}{100}\times x\)
% change
\(\dfrac{\text{change}}{\text{original}}\times100\%\)
Multiplier
Increase by 20% → multiply by 1.20. Decrease by 15% → multiply by 0.85.
Reverse %
After 20% increase, price = $360. Original = \(\dfrac{360}{1.2} = \$300\)
Reverse % trap: DO NOT subtract 20% from $360. Always divide by the multiplier.
Ratio & Proportion
Simplify
Write ratio in lowest terms: \(15:25 = 3:5\)
Sharing
Share £48 in ratio 3:5. Total parts = 8. One part = £6. Shares: £18 and £30.
Direct prop.
\(y\propto x\): \(y=kx\). Find \(k\) from one known pair, then use for others.
Inverse prop.
\(y\propto\frac{1}{x}\): \(y=\frac{k}{x}\). As \(x\) doubles, \(y\) halves.
Compound Interest vs Simple Interest
Simple: \(I = PRT\) (interest on original only)
Compound: \(A = P\left(1+\dfrac{r}{100}\right)^n\)

Principal £2000, rate 5%, 3 years:
Simple: \(I = 2000\times0.05\times3 = £300\)
Compound: \(A = 2000(1.05)^3 \approx £2315.25\)
Converting Between Forms
Fraction Decimal Percentage
½0.550%
¼0.2525%
¾0.7575%
\(0.\overline{3}\)33.3%
0.12512.5%
0.220%

Indices & Standard Form

Index laws · Negative & fractional indices · Standard form calculations

Index Laws — Summary
\(a^m \times a^n = a^{m+n}\)
\(\dfrac{a^m}{a^n} = a^{m-n}\)
\((a^m)^n = a^{mn}\)
\(a^0 = 1\)
\(a^{-n} = \dfrac{1}{a^n}\)
\(a^{p/q} = \left(\sqrt[q]{a}\right)^p\)
Fractional index rule: The denominator is the root, the numerator is the power. \(8^{2/3} = (\sqrt[3]{8})^2 = 4\). Always take the root first — then power.
Standard Form (Scientific Notation)
\(A \times 10^n\) where \(1 \leq A < 10\) and \(n\) is an integer
Large num.
\(4\,500\,000 = 4.5 \times 10^6\)
Small num.
\(0.0000032 = 3.2 \times 10^{-6}\)
Add/Sub
Convert to same power of 10 first, then add/subtract A values.
Multiply
Multiply A values, add exponents: \((3\times10^4)\times(2\times10^3)=6\times10^7\)
Divide
Divide A values, subtract exponents: \(\dfrac{6\times10^8}{2\times10^3}=3\times10^5\)
Worked Examples
Evaluate \(27^{-2/3}\):
\(\sqrt[3]{27}=3 \Rightarrow 3^2=9 \Rightarrow 27^{2/3}=9\)
So \(27^{-2/3}=\dfrac{1}{9}\)

Solve \(2^{3x+1}=8^{x-2}\):
\(8=2^3\Rightarrow 2^{3x+1}=2^{3(x-2)}\)
\(3x+1=3x-6\) — contradiction! No solution.

Estimate \(\dfrac{612\times 0.0049}{0.238}\):
\(\approx\dfrac{600\times0.005}{0.25}=\dfrac{3}{0.25}=12\)
Surds
Simplify
\(\sqrt{48}=\sqrt{16\times3}=4\sqrt{3}\)
Add/Sub
\(3\sqrt{5}+2\sqrt{5}=5\sqrt{5}\) (like terms only)
Multiply
\(\sqrt{3}\times\sqrt{12}=\sqrt{36}=6\)
Rationalise
\(\dfrac{4}{\sqrt{3}}=\dfrac{4\sqrt{3}}{3}\) — multiply by \(\dfrac{\sqrt{3}}{\sqrt{3}}\)
Conj. denom.
\(\dfrac{1}{3-\sqrt{2}}=\dfrac{3+\sqrt{2}}{(3)^2-(\sqrt{2})^2}=\dfrac{3+\sqrt{2}}{7}\)
Quick Surd Rules
\(\sqrt{a}\times\sqrt{a} = a\)
\(\sqrt{ab} = \sqrt{a}\times\sqrt{b}\)
\(\sqrt{\dfrac{a}{b}} = \dfrac{\sqrt{a}}{\sqrt{b}}\)
\((\sqrt{a}+\sqrt{b})(\sqrt{a}-\sqrt{b}) = a - b\)

Practice Questions

3 Easy · 3 Medium · 3 Hard — attempt first, then reveal full solution

Easy 1
[2] Find the HCF and LCM of 24 and 36.
STEP-BY-STEP SOLUTION
Factorise
\(24 = 2^3 \times 3\)   and   \(36 = 2^2 \times 3^2\)
HCF
Take minimum powers of common primes: \(2^2 \times 3 = \boldsymbol{12}\)
LCM
Take maximum powers of all primes: \(2^3 \times 3^2 = \boldsymbol{72}\)
Check: \(12 \times 72 = 864 = 24 \times 36\) ✓ (HCF × LCM = product of two numbers)
Easy 2
[2] Write \(0.000\,058\,3\) in standard form, and write \(4.07\times10^5\) as an ordinary number.
STEP-BY-STEP SOLUTION
Small → std
Move decimal 5 places right to get 5.83. \(\boldsymbol{5.83\times10^{-5}}\)
Std → ordinary
Move decimal 5 places right: \(\boldsymbol{407\,000}\)
Easy 3
[3] Without a calculator, evaluate:   (a) \(16^{3/4}\)   (b) \(125^{-2/3}\)
STEP-BY-STEP SOLUTION
(a) Root first
\(16^{3/4} = (\sqrt[4]{16})^3 = 2^3 = \boldsymbol{8}\)
(b) Root first
\(125^{2/3} = (\sqrt[3]{125})^2 = 5^2 = 25\)
(b) Negative
\(125^{-2/3} = \dfrac{1}{25} = \boldsymbol{0.04}\)
Medium 1
[4] A jacket costs £85 after a 15% discount. Find the original price. Also, if the shop then applies a 10% increase to the discounted price, is the result more than, less than, or equal to the original price?
STEP-BY-STEP — REVERSE PERCENTAGE
Multiplier
15% off → multiply by 0.85. So discounted = original × 0.85 = £85.
Original
Original = \(\dfrac{85}{0.85} = \boldsymbol{£100}\)
10% increase
£85 × 1.10 = £93.50
Compare
£93.50 < £100 (original). Net effect: −15% then +10% = ×0.85×1.10 = ×0.935 = 6.5% reduction overall.
Medium 2
[4] A length is measured as \(x = 12.4\) cm, rounded to 1 decimal place. Calculate the upper and lower bounds of the perimeter of a square with side \(x\), and state the perimeter to an appropriate degree of accuracy.
STEP-BY-STEP — BOUNDS
Bounds of x
Lower: \(12.35\) cm   Upper: \(12.45\) cm
Perimeter LB
\(4 \times 12.35 = \boldsymbol{49.4}\) cm
Perimeter UB
\(4 \times 12.45 = \boldsymbol{49.8}\) cm
Accuracy
Both bounds round to \(49.6\) cm (1 d.p.), so perimeter = \(\boldsymbol{49.6}\) cm (1 d.p.)
Medium 3
[3] Simplify \(\dfrac{(3.2\times10^7)\times(5\times10^{-3})}{4\times10^{-4}}\). Give your answer in standard form.
STEP-BY-STEP — STANDARD FORM CALCULATION
Numerator
\(3.2\times5=16\) and \(10^7\times10^{-3}=10^4\). Numerator: \(16\times10^4\)
Divide
\(\dfrac{16\times10^4}{4\times10^{-4}}=4\times10^{4-(-4)}=4\times10^8\)
Answer
\(\boldsymbol{4\times10^8}\)
Hard 1
[5] Prove that \(0.\overline{27}\) is rational by expressing it as a fraction in lowest terms. Hence show that the sum \(0.\overline{27} + 0.\overline{3}\) is a rational number and find it.
STEP-BY-STEP — RECURRING DECIMALS
Let x
\(x = 0.\overline{27} = 0.272727\ldots\)
100x
\(100x = 27.272727\ldots\)
Subtract
\(99x = 27 \Rightarrow x = \dfrac{27}{99} = \dfrac{3}{11}\)
Add
\(0.\overline{3} = \dfrac{1}{3}\). Sum: \(\dfrac{3}{11}+\dfrac{1}{3}=\dfrac{9}{33}+\dfrac{11}{33}=\boldsymbol{\dfrac{20}{33}}\)
Rational + Rational = Rational. \(\frac{20}{33}\) is in lowest terms (no common factor of 20 and 33). ✓
Hard 2
[5] Simplify \(\dfrac{\sqrt{75}-\sqrt{48}}{\sqrt{3}}\). Hence evaluate \(\left(\dfrac{\sqrt{75}-\sqrt{48}}{\sqrt{3}}\right)^3\) without a calculator.
STEP-BY-STEP — SURDS
Simplify surds
\(\sqrt{75}=5\sqrt{3}\) and \(\sqrt{48}=4\sqrt{3}\)
Numerator
\(5\sqrt{3}-4\sqrt{3}=\sqrt{3}\)
Simplify
\(\dfrac{\sqrt{3}}{\sqrt{3}}=\boldsymbol{1}\)
Cube
\(1^3=\boldsymbol{1}\)
Hard 3
[4] The population of a town decreases by 3% each year. In 2020 the population was 50,000.
(a) Find the population in 2025.
(b) Find the year when the population first falls below 40,000.
STEP-BY-STEP — COMPOUND DECREASE
(a)
\(P = 50000 \times (0.97)^5 = 50000 \times 0.8587 \approx \boldsymbol{42\,934}\)
(b) Inequality
\(50000\times(0.97)^n < 40000 \Rightarrow (0.97)^n < 0.8\)
(b) Log
\(n\ln(0.97)<\ln(0.8) \Rightarrow n>\dfrac{\ln0.8}{\ln0.97}\approx\dfrac{-0.2231}{-0.03046}\approx7.32\)
(b) Year
\(n=8\) → year \(2020+8=\boldsymbol{2028}\)
⚠ Log inequality: dividing by ln(0.97) which is negative flips the inequality sign.

Past Year Paper Questions

Cambridge IGCSE 0580 style — multi-part, show all working

0580 Style HCF, LCM & Primes
[9] (a) Write 360 as a product of its prime factors. [2]

(b) Find the HCF and LCM of 360 and 504. [3]

(c) Three lights flash at intervals of 12, 18 and 30 seconds. They all flash together at 09:00. When do they next all flash together? [4]
FULL WORKED SOLUTION
(a)
\(360 = 2^3 \times 3^2 \times 5\)
(b) Factorise
\(504 = 2^3 \times 3^2 \times 7\)
HCF = \(2^3\times3^2 = \boldsymbol{72}\)
LCM = \(2^3\times3^2\times5\times7 = \boldsymbol{2520}\)
(c) LCM
\(12=2^2\times3,\; 18=2\times3^2,\; 30=2\times3\times5\)
LCM \(=2^2\times3^2\times5=180\) seconds = 3 minutes
Next flash: \(\boldsymbol{09{:}03{:}00}\)
0580 Style Percentages & Compound Interest
[10] (a) In a sale, all prices are reduced by 20%. A television costs $480 in the sale. Find the original price. [2]

(b) Arjun invests $5000 at a compound interest rate of 4.5% per year. After how many whole years will his investment first exceed $6000? Show your working. [4]

(c) A car depreciates by 12% each year. It was bought for $18,000. Find its value after 3 years, and as a percentage of the original price. [4]
FULL WORKED SOLUTION
(a)
Original × 0.80 = $480. Original = \(\frac{480}{0.80} = \boldsymbol{\$600}\)
(b)
\(5000(1.045)^n > 6000 \Rightarrow (1.045)^n > 1.2\)
Try \(n=4\): \(1.045^4=1.193<1.2\). Try \(n=5\): \(1.045^5=1.246>1.2\).
Answer: \(\boldsymbol{n=5}\) years.
(c)
\(V = 18000\times(0.88)^3=18000\times0.6815=\boldsymbol{\$12\\,267}\)
Percentage: \(\frac{12267}{18000}\times100\approx\boldsymbol{68.2\%}\) of original
0580 Style Indices, Surds & Standard Form
[9] (a) Without using a calculator, evaluate \(\left(\dfrac{8}{27}\right)^{-2/3}\). [3]

(b) Simplify \(\left(\dfrac{2\sqrt{3}+\sqrt{2}}{\sqrt{2}}\right)^2\). [4]

(c) Calculate \(\dfrac{(3.6\times10^{-4})}{(1.2\times10^2)\times(5\times10^{-8})}\). Give your answer in standard form. [2]
FULL WORKED SOLUTION
(a)
\(\left(\frac{8}{27}\right)^{2/3} = \left(\sqrt[3]{\frac{8}{27}}\right)^2 = \left(\frac{2}{3}\right)^2 = \frac{4}{9}\)
Negative exponent: \(\boldsymbol{\frac{9}{4} = 2.25}\)
(b)
\(\dfrac{2\sqrt{3}+\sqrt{2}}{\sqrt{2}} = \dfrac{2\sqrt{3}}{\sqrt{2}}+1 = \sqrt{6}+1\)
Squaring: \((\sqrt{6}+1)^2=6+2\sqrt{6}+1=\boldsymbol{7+2\sqrt{6}}\)
(c)
Denominator: \(1.2\times5=6\) and \(10^2\times10^{-8}=10^{-6}\). Denom = \(6\times10^{-6}\).
\(\dfrac{3.6\times10^{-4}}{6\times10^{-6}}=0.6\times10^2=\boldsymbol{6\times10^1}\)